A spherical golf ball has its diameter determined with calipers as $(4.11 \pm 0.01)\ \text{cm}$. For a sphere, the volume is $V = \frac{1}{6}\pi d^{3}$, where $d$ represents the sphere’s diameter. What is the volume of the golf ball?
- A$(36.35 \pm 0.01)\ \text{cm}^{3}$
- B$(36.35 \pm 0.03)\ \text{cm}^{3}$
- C$(36.35 \pm 0.09)\ \text{cm}^{3}$
- D$(36.4 \pm 0.3)\ \text{cm}^{3}$