A micrometer screw gauge is employed to find the diameter of a wire. When the jaws are shut, the micrometer gives a reading of $(-0.05 \pm 0.02)\,\text{mm}$. With the wire placed between the two jaws, the reading becomes $(+1.03 \pm 0.02)\,\text{mm}$. Determine the diameter of the wire.
- A$(0.98 \pm 0.02)\,\text{mm}$
- B$(1.08 \pm 0.02)\,\text{mm}$
- C$(0.98 \pm 0.04)\,\text{mm}$
- D$(1.08 \pm 0.04)\,\text{mm}$