Physics 9702 · AS & A Level · Equilibrium of forces

Equilibrium of forces — practice question

(a)[1]

State what the term centre of gravity of a body means.

(b)

A uniform square sign with sides of length $0.68\,\text{m}$ is attached to a wall at its corner points A and B. The sign is also supported by a wire CD, as shown in Fig. 3.1. Its weight is $W$ and its centre of gravity is at point E. The sign is maintained in a vertical plane with side BC horizontal. The wire makes an angle of $35^{\circ}$ with side BC. The tension in the wire is $54\,\text{N}$. The force on the sign at B acts only vertically.

(b(i))[1]

Calculate the vertical part of the tension in the wire.

(b(ii))[1]

Explain why the force acting on the sign at B produces no moment about point A.

(b(iii))[2]

By taking moments about point A, show that the sign's weight $W$ is $150\,\text{N}$.

(b(iv))[1]

Calculate the combined vertical force exerted by the wall on the sign at points A and B.

(c)[4]

The sign in (b) is joined together by nuts and bolts. One nut drops vertically from rest through a distance of $4.8\,\text{m}$ to the pavement below. It reaches the pavement with a speed of $9.2\,\text{m s}^{-1}$. Determine, for the nut falling from the sign to the pavement, the ratio \(\frac{\text{change in gravitational potential energy}}{\text{final kinetic energy}}\).

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: Definition: the point at which the body's weight is treated as acting

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