A ball on level ground is kicked towards a vertical wall. Fig. 2.1 shows the trajectory of the ball. The ball leaves with an initial velocity $u$ at an angle of $38^\circ$ to the ground. It covers a horizontal distance of $9.0\,\text{m}$ before hitting the wall at a height $h$ above the ground. The horizontal component $u_h$ of the initial velocity of the ball is $9.5\,\text{m s}^{-1}$. Ignore air resistance.
(a(i))[1]
Show that the time $t$ taken for the ball to reach the wall is $0.95\,\text{s}$.
(a(ii))[2]
Calculate the vertical component $u_v$ of the initial velocity of the ball.
(a(iii))[2]
Determine $h$.
(b)[1]
The speed of the ball immediately after it hits the wall is lower than the speed immediately before impact. State what this suggests about the type of collision between the ball and the wall.
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Hence, $t = 9.0 / 9.5 = 0.95\ \text{s}$.” …