A projectile is launched from point $P$ with velocity $V$ at an angle $\theta$ above the horizontal. It reaches point $Q$, which is a horizontal distance $R$ from $P$, after a time $T$. The acceleration of free fall is $g$. Air resistance can be ignored. Which equation is correct?
- A$R = VT \cos \theta$
- B$R = VT \sin \theta$
- C$R = VT \cos \theta - \frac{1}{2} gT^2$
- D$R = VT \sin \theta - \frac{1}{2} gT^2$