For an object falling from rest on the Earth, the time taken to travel a vertical distance $h$ is $T_E$. For the same object falling from rest on the Moon, the time taken to travel the same vertical distance $h$ is $T_M$. The ratio $\frac{\text{acceleration of free fall on the Earth}}{\text{acceleration of free fall on the Moon}}$ is equal to $6$. Air resistance is negligible for the object on the Earth and on the Moon. Determine the ratio $\frac{T_E}{T_M}$?
- A$\frac{1}{6}$
- B$\frac{1}{\sqrt{6}}$
- C$\sqrt{6}$
- D$6$