Fig. 2.1 illustrates an object M on a slope. M travels upward along the slope, stops at point Q and then travels back down the slope to point R. M has a constant acceleration of $3.0\ \text{m s}^{-2}$ down the slope throughout. At time $t = 0$, M is at point P and has a velocity of $3.6\ \text{m s}^{-1}$ up the slope. The whole distance from P to Q and then on to R is $6.0\ \text{m}$.
(a(i))[2]
Calculate the time taken for M to move from P to Q.
(a(ii))[1]
Calculate the distance travelled for the motion of M from P to Q.
(b)[2]
Show that the speed of M at R is $4.8\ \text{m s}^{-1}$.
(c)[3]
On Fig. 2.2, draw the graph showing how the velocity $v$ of M changes with time $t$ for the motion from P to Q to R.
(d)[2]
The mass of M is $450\ \text{g}$. Calculate the difference in the kinetic energy of M at P and at R.
Worked solution & mark scheme
This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Application of $v = u + at$” …