As shown in Fig. 2.1, a ball is projected from ground level at point $P$. Its starting velocity is $12.4\,\text{m s}^{-1}$ and it is launched at an angle of $36^{\circ}$ above the horizontal. It just clears a wall of height $h$. The ball arrives at the wall $0.17\,\text{s}$ after being thrown.
(a(i))[2]
Assuming that air resistance is negligible, calculate the horizontal distance from point $P$ to the wall.
(a(ii))[3]
Assuming that air resistance is negligible, calculate the wall height $h$.
(b)[2]
A second ball is launched from point $P$ with the same velocity as the ball in part (a). For this ball, air resistance is not negligible. This ball hits the wall and rebounds. On Fig. 2.1, sketch the path of this ball between point $P$ and the point where it first hits the ground.
Worked solution & mark scheme
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “$V_H = 12.4\cos36^\circ = 10.0\,\text{m s}^{-1}$” …