The velocity-time graph shown here describes a stone that has been projected vertically upwards into the air. Air resistance can be ignored. The stone is released upwards at time zero. Area $X$ corresponds to a distance of $5\,\text{m}$. Area $Y$ corresponds to a distance of $3\,\text{m}$. What is the stone's displacement from its starting point at time $t$?
- A$2\,\text{m}$
- B$3\,\text{m}$
- C$5\,\text{m}$
- D$8\,\text{m}$