A projectile is launched from point $P$ with speed $V$ at an angle $\theta$ to the horizontal. It reaches point $Q$, which is a horizontal distance $R$ from $P$. Air resistance is negligible. The acceleration of free fall is $g$. Which expression for $R$ is correct?
- A$R = \dfrac{V^2 \sin\theta \cos\theta}{g}$
- B$R = \dfrac{2V^2 \sin\theta \cos\theta}{g}$
- C$R = \dfrac{V^2 \sin\theta \cos\theta}{2g}$
- D$R = \dfrac{V^2 g \sin\theta \cos\theta}{2}$