Physics 9702 · AS & A Level · Equations of motion

Equations of motion — practice question

A ball is projected from point $P$ with an initial velocity $u$ of $12\,\text{m s}^{-1}$ at $50^\circ$ above the horizontal, as shown in Fig. 2.1. The ball attains its greatest height at $Q$. Air resistance is negligible.
(a(i))[1]

Calculate the horizontal component of $u$.

(a(ii))[1]

Calculate the vertical component of $u$.

(b)[2]

Show that the maximum height reached by the ball is $4.3\,\text{m}$.

(c)[4]

Determine the magnitude of the displacement $PQ$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Horizontal component $= 12\cos 50^\circ = 7.7\ \text{m s}^{-1}$

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