Physics 9702 · AS & A Level · Equations of motion

Equations of motion — practice question

(a)[2]

Define speed and velocity, then use those definitions to explain why one of these quantities is scalar while the other is vector.

(b)

A ball is released from rest and falls vertically. The ball hits the ground and rebounds vertically, as shown in Fig. 2.1.

(b(i))[3]

Without calculation, use Fig. 2.2 to describe the variation with time $t$ of the velocity of the ball from $t = 0$ to $t = 2.1\,\text{s}$. Air resistance is negligible.

(b(ii))[3]

Calculate the acceleration of the ball after it rebounds from the ground. Show your working.

(b(iii)1)[3]

Calculate, for the ball, from $t = 0$ to $t = 2.1\,\text{s}$, the distance moved.

(b(iii)2)[2]

Calculate, for the ball, from $t = 0$ to $t = 2.1\,\text{s}$, the displacement from the initial position.

(b(iv))[2]

On Fig. 2.3, sketch the variation with $t$ of the speed of the ball.

(iii.1)[3]

Calculate, for the ball, from $t = 0$ to $t = 2.1\,\text{s}$, the distance moved.

(iii.2)[2]

Calculate, for the ball, from $t = 0$ to $t = 2.1\,\text{s}$, the displacement from the initial position.

(iv)[2]

On Fig. 2.3, sketch the variation with $t$ of the speed of the ball.

Worked solution & mark scheme

This 22-mark question has a full step-by-step worked solution and mark scheme. One marking point: Speed $=$ distance/time and velocity $=$ displacement/time

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI