A car with mass $500\,\text{kg}$ is stationary at point X on a slope, as illustrated. The brakes are then released, and the car travels down the slope with the engine turned off. By the time it reaches point Y, it has descended a vertical height of $30\,\text{m}$ and its speed is $11\,\text{m s}^{-1}$. What amount of energy is dissipated by frictional forces as the car travels from X to Y?
- A$3.0 \times 10^4\,\text{J}$
- B$1.2 \times 10^5\,\text{J}$
- C$1.5 \times 10^5\,\text{J}$
- D$1.8 \times 10^5\,\text{J}$