A spring with an unextended length of $0.10\,\text{m}$ hangs in a vertical position from a support. When a weight of $2.0\,\text{N}$ is hung from the lower end of the spring, its length becomes $0.15\,\text{m}$. A further weight of $4.0\,\text{N}$ is then attached to the spring’s lower end. The spring follows Hooke’s law. What extra elastic potential energy is stored in the spring as a result of adding the $4.0\,\text{N}$ weight?
- A$0.067\,\text{J}$
- B$0.13\,\text{J}$
- C$0.20\,\text{J}$
- D$0.40\,\text{J}$