Physics 9702 · AS & A Level · Atoms, nuclei and radiation

Atoms, nuclei and radiation — practice question

A nucleus of radioactive isotope $X$, initially at rest, decays by giving off an $\alpha$-particle, forming neptunium-237 and releasing $5.5\,\text{MeV}$ of energy. The decay is written as $X \rightarrow {}^{237}_{93}\text{Np} + \alpha + 5.5\,\text{MeV}$.
(a)[2]

Calculate the number of protons and the number of neutrons in a nucleus of $X$.

(b)[1]

Explain why the kinetic energy given to the $\alpha$-particle is smaller than the $5.5\,\text{MeV}$ of energy released in the decay.

(c(i))[2]

A sample of $X$ is used to generate a beam of $\alpha$-particles in a vacuum. The number of $\alpha$-particles passing a fixed point in the beam in $30\,\text{s}$ is $6.9 \times 10^{11}$. Calculate the mean current produced by the beam of $\alpha$-particles.

(c(ii))[2]

Determine the total power, in $\text{W}$, produced by the decay of $6.9 \times 10^{11}$ nuclei of $X$ in $30\,\text{s}$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: The number of protons is $95$.

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