Nuclide X has proton number $Z$ and undergoes $\beta^+$ decay to produce nuclide Y. This decay can be shown by the equation below. $X \rightarrow Y + \beta^+ + W$. What is the proton number of Y, and which particle does the symbol $W$ stand for?
- Aproton number of Y: $Z - 1$, particle: antineutrino
- Bproton number of Y: $Z - 1$, particle: neutrino
- Cproton number of Y: $Z + 1$, particle: antineutrino
- Dproton number of Y: $Z + 1$, particle: neutrino