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Solve the equation $2\tan^2\theta + 3\sec\theta = 18$ for $-180^\circ < \theta < 180^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve the equation $2\tan^2\theta + 3\sec\theta = 18$ for $-180^\circ < \theta < 180^\circ$.
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply an identity involving $\tan^2\theta$ and $\sec^2\theta$ to form a quadratic equation in $\sec\theta$ or $\cos\theta$” …