Draw the graph of $y = 3\sin x + 2$ for $0 \leq x \leq 2\pi$.
(b(i))[1]
Find the number of solutions, for $0 \leq x \leq 2\pi$, of the equation $3\sin x + 2 = x$.
(b(ii))[1]
Find the number of solutions, for $0 \leq x \leq 2\pi$, of the equation $3\sin x + 2 = 5 - x$.
(c)[5]
Solve $3\sin x + 2 = 5\cos^2 x - 1$ for $0 \leq x \leq 2\pi$.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “A complete curve for one cycle, with stationary points approximately at $\left(\frac\pi2,5\right)$ and $\left(\frac{3\pi}2,-1\right)$” …