Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a)[4]

Show that $\cos(\theta + 30^\circ)\cos(\theta + 60^\circ) = \frac{1}{4}\sqrt{3} - \frac{1}{2}\sin 2\theta$.

(b)[4]

Solve the equation $5\cos(2\alpha + 30^\circ)\cos(2\alpha + 60^\circ) = 1$ for values of $\alpha$ in the range $0^\circ < \alpha < 90^\circ$.

(c)[3]

Show that $\cos 20^\circ \cos 50^\circ + \cos 40^\circ \cos 70^\circ$ has exact value $\frac{1}{2}\sqrt{3}$.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: State $(\cos\theta\cos30-\sin\theta\sin30)(\cos\theta\cos60-\sin\theta\sin60)$

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