(a)[2]
Determine the value of $a$.
(b)[3]
Hence, factorise $p(x)$ fully.
(c)[3]
Solve $p(\cosec^2 \theta) = 0$ for $-90^\circ < \theta < 90^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
The polynomial $p(x)$ is given by $p(x) = ax^3 - ax^2 - 15x + 18$, with $a$ as a constant. It is stated that $(x + 2)$ is one factor of $p(x)$.
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