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Determine the exact solution to the equation $\cos \frac{\pi}{6} + \tan 2x + \frac{\sqrt{3}}{2} = 0$ for $-\frac{1}{4}\pi < x < \frac{1}{4}\pi$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
Worked solution & mark scheme
This 2-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Rearranging $\cos\left(\frac{\pi}{6}\right)+\tan2x+\sqrt{3}=0$ so that $\tan2x$ is the subject, giving $\tan2x=-\sqrt{3}$.” …
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