Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a)[3]

It is given that $\beta$ is an angle between $90^\circ$ and $180^\circ$ for which $\sin \beta = a$. Express $\tan^2 \beta - 3 \sin \beta \cos \beta$ in terms of $a$.

(b)[5]

Solve the equation $\sin^2 \theta + 2 \cos^2 \theta = 4 \sin \theta + 3$ for $0^\circ < \theta < 360^\circ$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Rewrite using $\tan^2\beta=\dfrac{\sin^2\beta}{\cos^2\beta}$

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