Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a)[3]

Prove that $4\sin x\sin\left(x + \tfrac{1}{6}\pi\right) \equiv \sqrt{3} - \sqrt{3}\cos 2x + \sin 2x$.

(b)[4]

Find the exact value of $\displaystyle \int_{0}^{\tfrac{5}{6}\pi} 4\sin x\sin\left(x + \tfrac{1}{6}\pi\right)\, dx$.

(c)[3]

Find the least positive value of $y$ that satisfies the equation $4\sin(2y)\sin\left(2y + \frac{\pi}{6}\right) = \sqrt{3}$. Give your answer exactly.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: State the expression $4\sin x(\sin x\cos\tfrac{\pi}{6}+\cos x\sin\tfrac{\pi}{6})$.

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