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Solve, by factorising, $6\cos\theta\tan\theta - 3\cos\theta + 4\tan\theta - 2 = 0$, for $0^\circ \leq \theta \leq 180^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve, by factorising, $6\cos\theta\tan\theta - 3\cos\theta + 4\tan\theta - 2 = 0$, for $0^\circ \leq \theta \leq 180^\circ$.
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “A partially factorised form of an expression that involves $\tan\theta$ and $\cos\theta$” …