Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

A curve is given by the parametric equations $x = 3t - 2\sin t$, $y = 5t + 4\cos t$, with $0 \leq t \leq 2\pi$. At the two points $P$ and $Q$ on the curve, the gradient equals $\frac{5}{2}$.
(a)[3]

Show that the $t$-values at $P$ and $Q$ satisfy the equation $10\cos t - 8\sin t = 5$.

(b)[3]

Express $10\cos t - 8\sin t$ in the form $R\cos(t + \alpha)$, where $R > 0$ and $0 < \alpha < \frac{1}{2}\pi$. State the exact value of $R$ and give $\alpha$ correct to 3 significant figures.

(c)[4]

Hence find the corresponding $t$-values at $P$ and $Q$.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: Find $\dfrac{dx}{dt}=3-2\cos t$ and $\dfrac{dy}{dt}=5-4\sin t$

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