(i)[4]
Show that the equation $\sqrt{2}\,\cosec x + \cot x = \sqrt{3}$ can be written in the form $R\sin(x - \alpha) = \sqrt{2}$, where $R > 0$ and $0^\circ < \alpha < 90^\circ$.
(ii)[4]
Hence solve the equation $(\sqrt{2})\cesec x + \cot x = \sqrt{3}$ when $0^\circ < x < 180^\circ$.