Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(i)[4]

Show that the equation $(\sqrt{2})\cosec x + \cot x = \sqrt{3}$ may be written in the form $R\sin(x - \alpha) = \sqrt{2}$, where $R > 0$ and $0^\circ < \alpha < 90^\circ$.

(ii)[4]

Hence solve the equation $\sqrt{2}\,\cosec x + \cot x = \sqrt{3}$, for $0^\circ<x<180^\circ$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Put the expression into the form $\sqrt3\sin x-\cos x=\sqrt2$

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