(i)[3]
Show that the equation $$\frac{\cos \theta - 4}{\sin \theta} - \frac{4 \sin \theta}{5 \cos \theta - 2} = 0$$ may be rewritten as $$9 \cos^2 \theta - 22 \cos \theta + 4 = 0.$$
(ii)[3]
Hence solve the equation $$\frac{\cos \theta - 4}{\sin \theta} - \frac{4 \sin \theta}{5 \cos \theta - 2} = 0$$ for $0^\circ \leq \theta \leq 360^\circ$.