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Rewrite $\sec \theta = 3 \cos \theta + \tan \theta$ as a quadratic equation in $\sin \theta$. Hence solve the equation for $-90^\circ < \theta < 90^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Rewrite $\sec \theta = 3 \cos \theta + \tan \theta$ as a quadratic equation in $\sin \theta$. Hence solve the equation for $-90^\circ < \theta < 90^\circ$.
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Correctly rewrite the equation in terms of $\sin\theta$ and $\cos\theta$” …