(i)[2]
Rewrite the equation $\sin 2x + 3\cos 2x = 3(\sin 2x - \cos 2x)$ so that it takes the form $\tan 2x = k$, where $k$ is a constant.
(ii)[3]
Hence solve the equation for $-90^\circ \leq x \leq 90^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Rewrite the equation $\sin 2x + 3\cos 2x = 3(\sin 2x - \cos 2x)$ so that it takes the form $\tan 2x = k$, where $k$ is a constant.
Hence solve the equation for $-90^\circ \leq x \leq 90^\circ$.
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Obtains $2\sin2x = 6\cos2x$ and then changes this to $\tan2x=k$.” …