(i)[2]
Use the factor theorem to establish that $a = -4$.
(ii(a))[3]
When $a = -4$, completely factorise $p(x)$.
(ii(b))[2]
Solve the equation $6\sec^3\theta + 11\sec^2\theta + a\sec\theta + a = 0$ for $0^\circ \leq \theta \leq 180^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
The polynomial $p(x)$ is given by $p(x) = 6x^3 + 11x^2 + ax + a$, where $a$ is a constant. It is also stated that $(x + 2)$ is a factor of $p(x)$.