(i)[3]
Demonstrate that $1 + \sin x \tan x = 5\cos x$ can be rearranged into $6\cos^2 x - \cos x - 1 = 0$.
(ii)[3]
Hence solve $1 + \sin x \tan x = 5\cos x$ for $0^\circ \leq x \leq 180^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Mathematics 9709 · AS & A Level · Trigonometry
Demonstrate that $1 + \sin x \tan x = 5\cos x$ can be rearranged into $6\cos^2 x - \cos x - 1 = 0$.
Hence solve $1 + \sin x \tan x = 5\cos x$ for $0^\circ \leq x \leq 180^\circ$.