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Solve $7\cos x + 5 = 2\sin^2 x$, for $0^\circ \leq x \leq 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve $7\cos x + 5 = 2\sin^2 x$, for $0^\circ \leq x \leq 360^\circ$.
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Applies the identity $\cos^2 x + \sin^2 x = 1$ to reach a factorised form.” …