(main)[6]
Solve the equation $5\sec^2 2\theta = \tan 2\theta + 9$, giving every solution in the interval $0^\circ \leq \theta \leq 180^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve the equation $5\sec^2 2\theta = \tan 2\theta + 9$, giving every solution in the interval $0^\circ \leq \theta \leq 180^\circ$.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply the trigonometric identity correctly to form a quadratic in $\tan 2\theta$” …