(a)[3]
Prove that $\frac{\sin x \tan x}{1 - \cos x} = 1 + \frac{1}{\cos x}$.
(b)[3]
Hence solve $\frac{\sin x \tan x}{1 - \cos x} + 2 = 0$, for $0^{\circ} \leq x \leq 360^{\circ}$.
Mathematics 9709 · AS & A Level · Trigonometry
Mathematics 9709 · AS & A Level · Trigonometry
Prove that $\frac{\sin x \tan x}{1 - \cos x} = 1 + \frac{1}{\cos x}$.
Hence solve $\frac{\sin x \tan x}{1 - \cos x} + 2 = 0$, for $0^{\circ} \leq x \leq 360^{\circ}$.