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Solve $6\sin\theta = 1 + \frac{2}{\sin\theta}$ over the range $-180^{\circ} < \theta < 180^{\circ}$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve $6\sin\theta = 1 + \frac{2}{\sin\theta}$ over the range $-180^{\circ} < \theta < 180^{\circ}$.
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Express the equation as a 3-term quadratic, for example $6\sin^2\theta-\sin\theta-2=0$, or as an equivalent factorised form.” …