Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

Consider the function $f(x) = 8x^3 + 54x^2 - 17x - 21$.
(a)[1]

Show that $f(x)$ has $x + 7$ as a factor.

(b)[2]

Determine the quotient obtained when $f(x)$ is divided by $x + 7$.

(c)[3]

Hence solve the equation $8\cos^3\theta + 54\cos^2\theta - 17\cos\theta - 21 = 0$, with $0^\circ \leq \theta \leq 360^\circ$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Show $8(-7)^3+54(-7)^2-17(-7)-21=0$ or use division to reach the equivalent result

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