Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a)[4]

Show that the expression $3\tan 2\theta + \tan(\theta + 45^\circ)$ is equivalent to $\dfrac{\tan^2\theta + 8\tan\theta + 1}{1 - \tan^2\theta}$.

(b)[3]

Hence solve $3\tan 2\theta + \tan(\theta + 45^\circ) = 4$ for $0^\circ < \theta < 180^\circ$.

Worked solution & mark scheme

This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: State the identity $3\tan 2\theta = \dfrac{6\tan\theta}{1-\tan^2\theta}$

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