(a)[3]
Show that $\frac{7\tan\theta}{\cos\theta} + 12 = 0$ may be rewritten as $12\sin^2\theta - 7\sin\theta - 12 = 0$.
(b)[3]
Hence solve $\frac{7\tan\theta}{\cos\theta} + 12 = 0$ for $0^\circ \leq \theta \leq 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Trigonometry — practice question
Worked solution & mark scheme
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Uses $\tan\theta=\frac{\sin\theta}{\cos\theta}$ to set up the equation” …
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