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Find the solutions of the equation $\sec^2 \theta + 5\tan^2 \theta = 9 + 17\sec \theta$ for $0^{\circ} < \theta < 360^{\circ}$.
Mathematics 9709 · AS & A Level · Trigonometry
Find the solutions of the equation $\sec^2 \theta + 5\tan^2 \theta = 9 + 17\sec \theta$ for $0^{\circ} < \theta < 360^{\circ}$.
This 5-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Rewrite the equation so that it is expressed using only $\sec \theta$ (or, equivalently, only $\cos \theta$)” …