(a)[4]
Solve $6\sqrt{y} + \frac{2}{\sqrt{y}} - 7 = 0$.
(b)[3]
Hence determine all solutions to $6\sqrt{\tan x} + \frac{2}{\sqrt{\tan x}} - 7 = 0$ for $0^\circ \leq x \leq 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve $6\sqrt{y} + \frac{2}{\sqrt{y}} - 7 = 0$.
Hence determine all solutions to $6\sqrt{\tan x} + \frac{2}{\sqrt{\tan x}} - 7 = 0$ for $0^\circ \leq x \leq 360^\circ$.
This 7-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Rearrange into a 3-term quadratic, for example $6y + 2 - 7y^{\frac{1}{2}}=0$” …