Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a)[4]

From the equation $\cos(x - 30^{\circ}) = 2\sin(x + 30^{\circ})$, show that $\tan x = \frac{2 - \sqrt{3}}{1 - 2\sqrt{3}}$.

(b)[2]

Hence solve the equation $\cos(x - 30^{\circ}) = 2\sin(x + 30^{\circ})$, for values of $x$ satisfying $0^{\circ} < x < 360^{\circ}$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Apply the correct trigonometric expansions and derive an equation involving $\sin x$ and $\cos x$

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