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Solve $ \sin(2\theta + 30^{\circ}) = 5\cos(2\theta + 60^{\circ})$ for $0^{\circ} < \theta < 180^{\circ}$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve $ \sin(2\theta + 30^{\circ}) = 5\cos(2\theta + 60^{\circ})$ for $0^{\circ} < \theta < 180^{\circ}$.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Correctly expand at least one of $\sin(2\theta+30)$ or $\cos(2\theta+60)$” …