Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

The polynomial $p(x)$ is specified by $p(x)=6x^3+ax^2-4x-3$, with $a$ as a constant. You are told that $(x+3)$ is a factor of $p(x)$.
(a)[2]

Determine the value of $a$.

(b)[3]

Using this value of $a$, factorise $p(x)$ fully.

(c)[3]

Hence find the solutions of $p(\cosec\,\theta)=0$ for $0^\circ < \theta < 360^\circ$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Substitute $x=-3$, set the result equal to zero and try to solve for $a$

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