Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

The polynomial $p(x)$ is given by $p(x) = 6x^3 + ax^2 - 4x - 3$, with $a$ as a constant. It is known that $(x + 3)$ is a factor of $p(x)$.
(a)[2]

Determine the value of $a$.

(b)[3]

With this value of $a$, completely factorise $p(x)$.

(c)[3]

Hence solve the equation $p(\cosec\,\theta) = 0$ for $0^\circ < \theta < 360^\circ$.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Substitute $x = -3$, set the result to zero and try to solve for $a$

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