(i)[4]
If $\sin(x - 60^\circ) = 3\cos(x - 45^\circ)$, determine the exact value of $\tan x$.
(ii)[2]
Hence solve the equation $\sin(x - 60^\circ) = 3\cos(x - 45^\circ)$ in the interval $0^\circ < x < 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
If $\sin(x - 60^\circ) = 3\cos(x - 45^\circ)$, determine the exact value of $\tan x$.
Hence solve the equation $\sin(x - 60^\circ) = 3\cos(x - 45^\circ)$ in the interval $0^\circ < x < 360^\circ$.
This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Apply trigonometric formulae to obtain an equation involving only $\sin x$ and $\cos x$” …