(a(i))[3]
Write $(\sqrt{5})\cos x + 2\sin x$ in the form $R\cos(x - \alpha)$, where $R > 0$ and $0^\circ < \alpha < 90^\circ$, and give $\alpha$ correct to 2 decimal places.
(a(ii))[3]
Hence, solve $(\sqrt{5})\cos\left(\frac{x}{2}\right) + 2\sin\left(\frac{x}{2}\right) = 1.2$ for $0^\circ < x < 360^\circ$.