Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(main)[4]

Solve the equation $3\sin^2\theta = 4\cos\theta - 1$ for values of $\theta$ in the interval $0^\circ \leq \theta \leq 360^\circ$.

Worked solution & mark scheme

This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: Form an equation in $\cos\theta$ from $3\sin^2\theta = 4\cos\theta -1$ and $\sin^2\theta + \cos^2\theta = 1$.

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