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Solve the equation $3\sin^2\theta = 4\cos\theta - 1$ for values of $\theta$ in the interval $0^\circ \leq \theta \leq 360^\circ$.
Mathematics 9709 · AS & A Level · Trigonometry
Solve the equation $3\sin^2\theta = 4\cos\theta - 1$ for values of $\theta$ in the interval $0^\circ \leq \theta \leq 360^\circ$.
This 4-mark question has a full step-by-step worked solution and mark scheme. One marking point: “Form an equation in $\cos\theta$ from $3\sin^2\theta = 4\cos\theta -1$ and $\sin^2\theta + \cos^2\theta = 1$.” …