Mathematics 9709 · AS & A Level · Trigonometry

Trigonometry — practice question

(a(i))[3]

Demonstrate that the equation $\tan(x - 60^\circ) + \cot x = \sqrt{3}$ can be rearranged into the form $2\tan^2 x + (\sqrt{3})\tan x - 1 = 0$.

(a(ii))[3]

Hence, solve the equation $\tan(x - 60^\circ) + \cot x = \sqrt{3}$ for $0^\circ < x < 180^\circ$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: Apply the $\tan(A\pm B)$ formula and form an equation in $\tan x$

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