(i)[3]
Prove that $\frac{\tan x + 1}{\sin x \tan x + \cos x} \equiv \sin x + \cos x$.
(ii)[3]
Hence determine the values of $x$ for $0 \le x \le 2\pi$ that satisfy $\frac{\tan x + 1}{\sin x \tan x + \cos x} = 3\sin x - 2\cos x$.
Mathematics 9709 · AS & A Level · Trigonometry